Integrand size = 20, antiderivative size = 49 \[ \int (b x)^m (\pi +d x)^n (e+f x)^p \, dx=\frac {e^p \pi ^n (b x)^{1+m} \operatorname {AppellF1}\left (1+m,-n,-p,2+m,-\frac {d x}{\pi },-\frac {f x}{e}\right )}{b (1+m)} \]
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Time = 0.02 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.050, Rules used = {138} \[ \int (b x)^m (\pi +d x)^n (e+f x)^p \, dx=\frac {\pi ^n e^p (b x)^{m+1} \operatorname {AppellF1}\left (m+1,-n,-p,m+2,-\frac {d x}{\pi },-\frac {f x}{e}\right )}{b (m+1)} \]
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Rule 138
Rubi steps \begin{align*} \text {integral}& = \frac {e^p \pi ^n (b x)^{1+m} F_1\left (1+m;-n,-p;2+m;-\frac {d x}{\pi },-\frac {f x}{e}\right )}{b (1+m)} \\ \end{align*}
Time = 0.15 (sec) , antiderivative size = 45, normalized size of antiderivative = 0.92 \[ \int (b x)^m (\pi +d x)^n (e+f x)^p \, dx=\frac {e^p \pi ^n x (b x)^m \operatorname {AppellF1}\left (1+m,-n,-p,2+m,-\frac {d x}{\pi },-\frac {f x}{e}\right )}{1+m} \]
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\[\int \left (b x \right )^{m} \left (d x +\pi \right )^{n} \left ({\mathrm e}+f x \right )^{p}d x\]
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\[ \int (b x)^m (\pi +d x)^n (e+f x)^p \, dx=\int { {\left (\pi + d x\right )}^{n} \left (b x\right )^{m} {\left (f x + e\right )}^{p} \,d x } \]
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\[ \int (b x)^m (\pi +d x)^n (e+f x)^p \, dx=\int \left (b x\right )^{m} \left (d x + \pi \right )^{n} \left (f x + e\right )^{p}\, dx \]
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\[ \int (b x)^m (\pi +d x)^n (e+f x)^p \, dx=\int { {\left (\pi + d x\right )}^{n} \left (b x\right )^{m} {\left (f x + e\right )}^{p} \,d x } \]
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\[ \int (b x)^m (\pi +d x)^n (e+f x)^p \, dx=\int { {\left (\pi + d x\right )}^{n} \left (b x\right )^{m} {\left (f x + e\right )}^{p} \,d x } \]
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Timed out. \[ \int (b x)^m (\pi +d x)^n (e+f x)^p \, dx=\int {\left (\mathrm {e}+f\,x\right )}^p\,{\left (b\,x\right )}^m\,{\left (\Pi +d\,x\right )}^n \,d x \]
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